Statement 1: $\Big(\dfrac{3}{4}\Big)^{-4} \times \Big(\dfrac{3}{4}\Big)^{-5} = \Big(\dfrac{3}{4}\Big)^{3x}$

⇒ x = -1

Statement 2: $\Big(\dfrac{3}{4}\Big)^{-4 - 5} = \Big(\dfrac{3}{4}\Big)^{3x}$

⇒ 3x = -9

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Statement 1: $\Big(\dfrac{5}{8}\Big)^{-7} \times \Big(\dfrac{8}{5}\Big)^{-4} = x$

⇒ x = $\Big(\dfrac{5}{8}\Big)^{3}$

Statement 2: $\Big(\dfrac{5}{8}\Big)^{-7} \times \Big(\dfrac{5}{8}\Big)^{4} = x$

⇒ x = $\Big(\dfrac{8}{5}\Big)^{3}$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Assertion (A): (1³ + 2³ + 3³)$^\frac{1}{2}$ = x, then x = $\sqrt{1} + \sqrt{8} + \sqrt{27}$.

Reason (R): x = (1 + 8 + 27)$^\frac{1}{2} = 36^\frac{1}{2} = 6$

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.

Evaluate :

$9^{\dfrac{5}{2}} - 3 \times 8^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}}$