Statement 1: If x = $\sqrt{5} + 2$, then $x - \dfrac{1}{x} = 4.$

Statement 2: $\dfrac{1}{x} = \dfrac{1}{\sqrt{5} + 2} \times \dfrac{\sqrt{5} - 2}{\sqrt{5} - 2} = \sqrt{5} - 2$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Assertion (A): $x + \dfrac{1}{x} = 4 \text{ and } \dfrac{1}{x} = 2 + \sqrt{3}, \text{ then x } = 2 - \sqrt{3}$

Reason (R):

$\Rightarrow \dfrac{1}{x} = 2 + \sqrt{3}\\[1em] \Rightarrow x = \dfrac{1}{2 + \sqrt{3}} = 2 - \sqrt{3}$

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.

Simplify :

$\dfrac{\sqrt{x^2 + y^2} - y}{x - \sqrt{x^2 - y^2}} ÷ \dfrac{\sqrt{x^2 - y^2} + x}{\sqrt{x^2 + y^2} + y}$

Evaluate, correct to one place of decimal, the expression $\dfrac{5}{\sqrt{20} - \sqrt{10}}, \text{ if } \sqrt{5} = 2.2 \text{ and } \sqrt{10} = 3.2$