Mathematics
Assertion (A): In the given figure, if O is the centre of the circle, then ∠ACB = 40°.
Reason (R): Angle at the centre is double the angle at the remaining part of the circle.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false

Circles
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Answer
From figure,
OA = OB (Radii of same circle)
∠OBA = ∠OAB = 50° (As angles opposite to equal sides in a triangle are equal)
∠OBA + ∠OAB + ∠AOB = 180° [Angle sum property of a triangle]
50° + 50° + ∠AOB = 180°
100° + ∠AOB = 180°'
∠AOB = 180° - 100°
∠AOB = 80°.
We know that,
Angle which an arc subtends at the center is double that which it subtends at any point on the remaining part of the circumference.
So, reason (R) is true.
∠AOB = 2∠ACB
∠ACB = = 40°.
So, Assertion (A) is true.
Both A and R are true.
Hence, option 3 is the correct option.
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Related Questions
In the given figure, O is the centre of the circle, ∠AOB = 40° and ∠BDC = 100°. The measure of ∠OBC is :
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ABCD is a cyclic quadrilateral. If ∠BAD = (2x + 5)° and ∠BCD = (x + 10)°, then x is equal to :
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Assertion (A): In the figure, ∠ACB = 70°.
Reason (R): Opposite angles of a cyclic quadrilateral are equal.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false

Assertion (A): In the figure, if AB is a diameter of the circle, then ∠BAC = 50°.
Reason (R): Sum of two angles of a cyclic quadrilateral is always 180°.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
