Mathematics
Assertion (A): The line segment joining the mid-points of all parallel chords of a circle passes through the centre.
Reason (R): If the chords are on same side of centre then only the line through the mid-points of the chords passes through the centre.
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
Circles
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Answer
A is true, R is false.
Explanation

Let AB and CD be two parallel chords of a circle with center O. P is mid-point of AB and Q is mid-point of CD.
We have to prove that the line joining the points P and Q passes through the center O, i.e., ∠ POQ = 180°.
Construction : Join OP and OQ. Also, draw OE parallel to AB and CD.
Proof : Since, line segment joining the mid-point of the chord with the center of the circle is perpendicular to the chord, therefore, OP is perpendicular to AB and OQ is perpendicular to CD.
⇒ ∠ OPA = 90° and ∠ OQC = 90°
Now, OE ∥ AB and OP is transversal.
∴ ∠ POE = ∠ OPA = 90° (Alternate angles)
Similarly, OE ∥ CD and OQ is transversal.
∴ ∠ QOE = ∠ OQC = 90° (Alternate angles)
∴ ∠ POQ = ∠ POE + ∠ QOE
= 90° + 90°
= 180°
⇒ POQ is a straight line.
i.e, the line joining the mid-points of two parallel chords passes through the center.
∴ Assertion (A) is true.

Let AB and CD be two parallel chords that are lying on the same side of a circle with center O. M is mid-point of AB and N is mid-point of CD.
We have to prove that the line joining the points M and N passes through the center O, i.e., ∠ MNO = 180°.
Construction : Join OM and ON. Also, draw OE parallel to AB and CD.
Proof : Since, line segment joining the mid-point of the chord with the center of the circle is perpendicular to the chord, therefore, OM is perpendicular to AB and ON is perpendicular to CD.
⇒ ∠ OMA = 90° and ∠ ONC = 90°
Now, OE ∥ AB and OM is transversal.
∴ ∠ MOE = ∠ OMA = 90° (Alternate angles)
Similarly, OE ∥ CD and ON is transversal.
∴ ∠ NOE = ∠ ONC = 90° (Alternate angles)
∴ ∠ MNO = ∠ MND + ∠ DNO
= ∠ MNC + ∠ CNO
= 90° + 90°
= 180°
⇒ MNO is a straight line.
i.e, The line passing through M and N also passes through O.
∴ Reason (R) is false.
Hence, Assertion (A) is true, Reason (R) is false.
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Related Questions
Assertion (A): AM and BN are tangents to the same circle at points A and B respectively. Then AN = BM.

Reason (R): Since, tangents to a circle are equal in length
⇒ AM = BN
△APN ≅ △BPM ⇒ AN = BM
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