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Mathematics

Assertion (A): The number obtained on rationalizing the denominator of 152\dfrac{1}{\sqrt{5} - 2} is 2+52 + \sqrt{5}.

Reason (R): If the product of two irrational numbers is rational, then each one is called the rationalizing factor of the other.

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false.

Rational Irrational Nos

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Answer

Given,

152\dfrac{1}{\sqrt{5} - 2}

Rationalizing the denominator of 152\dfrac{1}{\sqrt{5} - 2},

152×5+25+25+2(5)2(2)25+2545+212+5\Rightarrow \dfrac{1}{\sqrt{5} - 2} \times \dfrac{\sqrt{5} + 2}{\sqrt{5} + 2} \\[1em] \Rightarrow \dfrac{\sqrt{5} + 2}{(\sqrt{5})^2 - (2)^2}\\[1em] \Rightarrow \dfrac{\sqrt{5} + 2}{5 - 4} \\[1em] \Rightarrow \dfrac{\sqrt{5} + 2}{1} \\[1em] \Rightarrow 2 + \sqrt{5}

∴ Assertion (A) is true.

We know that,

If the product of two irrational numbers is rational, then each one is called the rationalizing factor of the other.

∴ Reason (R) is true.

Hence, Option 3 is the correct option.

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