Mathematics
Assertion (A): Each of the numbers is irrational.
Reason (R): The cube roots of all natural numbers is irrational.
A is true, R is false
Both A and R are true
A is false, R is true
Both A and R are false.
Rational Irrational Nos
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Answer
are irrational, because these are cube roots of not perfect cubes.
∴ Assertion (A) is true.
The cube roots of all perfect cubes are rational. Thus, we cannot say that the cube roots of all natural numbers is irrational.
∴ Reason (R) is false.
Hence, Option 1 is the correct option.
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Related Questions
Case Study
Ms Mehta teaches maths in a school. One day after teaching the lesson of number system, she wanted to check the understanding of the students of her class. So, she wrote two numbers, on the blackboard and asked few questions based on them. You please try to answer the following questions asked by Ms Mehta.
The decimal expansion of is:
(a) terminating
(b) non-terminating
(c) non-terminating non-repeating
(d) non-terminating repeatingis:
(a) non-terminating non-repeating
(b) non-terminating repeating
(c) non-terminating
(d) terminatingThe decimal form of :
(a) 0.27
(b) 0.2727
(c)
(d) 0.3as vulgar fraction becomes:
(a)
(b)
(c)
(d)The sum of is :
(a)
(b)
(c)
(d)
Assertion (A): The number obtained on rationalizing the denominator of is .
Reason (R): If the product of two irrational numbers is rational, then each one is called the rationalizing factor of the other.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false.
The sum of all rational numbers between 0 and 0.1 is :
finite
infinite
can't say anything
none of these
Four rational numbers p, q, r and s are such that q is the reciprocal of p and s is the reciprocal of r. The value of the expression is equal to:
1
0
pr