Mathematics
Assertion (A): In parallelogram ABCD, PD bisects ∠ADC and PC bisects angle DCB, then ∠DPC = 90°. Reason (R): ∠PDC = x ∠ADC ∠PCD = x ∠BCD ∠PDC + ∠PCD = x (∠ADC + ∠BCD) 1. A is true, but R is false. 2. A is false, but R is true. 3. Both A and R are true, and R is the correct reason for A. 4. Both A and R are true, and R is the incorrect reason for A.
Related Questions
Statement 1: Through a vertex of a polygon, 3 diagonals can be drawn.
Statement 2: The polygon is hexagon.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Assertion (A): The diagonal of a quadrilateral bisect each other at right angle.
Reason (R): The quadrilateral is square.
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6°. Find the value of n.
Two alternate sides of a regular polygon, when produced, meet at right angle. Find :
(i) the value of each exterior angle of the polygon;
(ii) the number of sides in the polygon.