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Mathematics

Assertion (A): (1+tanθ1+cotθ)2=tan2θ\Big(\dfrac{1 + \tan \theta}{1 + \cot \theta} \Big)^2 = \tan^2 \theta

Reason (R): tan2 θ + sec2 θ = 1

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Trigonometric Identities

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Answer

(1+tanθ1+cotθ)2(1+tanθ1+1tanθ)2(1+tanθtanθ+1tanθ)2tan2θ\Rightarrow \Big(\dfrac{1 + \tan \theta}{1 + \cot \theta} \Big)^2 \\[1em] \Rightarrow \Big(\dfrac{1 + \tan \theta}{1 + \dfrac{1}{\tan \theta}} \Big)^2 \\[1em] \Rightarrow \Big(\dfrac{1 + \tan \theta}{ \dfrac{\tan \theta + 1}{\tan \theta}} \Big)^2 \\[1em] \Rightarrow \tan^2 \theta

Therefore, assertion (A) is true.

tan2 θ + sec2 θ = 1 is incorrect

The correct identity is sec2 θ - tan2 θ = 1

Therefore, reason (R) is false.

A is true, R is false.

Hence, option 1 is the correct option.

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