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Mathematics

Assertion (A): From a solid wooden cylinder of height 15 cm and diameter 14 cm, a hemispherical depression of same base diameter is carved out. The volume of remaining wood is 1591131591\dfrac{1}{3} cm3.

Reason (R): The volume of a cylinder of height h and radius r is πr2h and the volume of a hemisphere of radius r is 23\dfrac{2}{3} πr3.

Mensuration

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Answer

Given,

Height of cylinder,(H) = 15 cm

Diamter of cylinder, (D) = 14 cm

Radius of cylinder, r = D2=142\dfrac{D}{2} = \dfrac{14}{2} = 7 cm

Radius of hemisphere, (r) = 7 cm

The volume of a cylinder is πr2h and the volume of a hemisphere is 23\dfrac{2}{3} πr3.

So, reason (R) is true.

Volume of remaining wood = Volume of cylinder - Volume of hemisphere

=πR2H23πr3=227×72×1523×227×73=22×7×1523×22×72=231021563=693021563=47743=159113= πR^2H - \dfrac{2}{3}πr^3\\[1em] = \dfrac{22}{7} \times 7^2 \times 15 - \dfrac{2}{3}\times \dfrac{22}{7} \times 7^3\\[1em] = 22 \times 7 \times 15 - \dfrac{2}{3}\times 22 \times 7^2\\[1em] = 2310 - \dfrac{2156}{3}\\[1em] = \dfrac{6930 - 2156}{3}\\[1em] = \dfrac{4774}{3}\\[1em] = 1591\dfrac{1}{3}\\[1em]

So, assertion (A) is true.

Thus, both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

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