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Mathematics

Assertion (A): For triangle ABC, sec (A+B2)=cosec C\Big(\dfrac{A+B}{2}\Big) = \text{cosec C}.

Reason (R): sec (90° - θ) = cosec θ.

  1. A is true, R is false.
  2. A is false, R is true.
  3. Both A and R are true.
  4. Both A and R are false.

Trigonometric Identities

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Answer

A is false, R is true.

Explanation

In triangle ABC,

∠ A + ∠ B + ∠ C = 180°

⇒ ∠ A + ∠ B = 180° - ∠ C

A+B2=180°C2\dfrac{∠ A + ∠ B}{2} = \dfrac{180° - ∠ C}{2}

A+B2=90°C2\dfrac{∠ A + ∠ B}{2} = 90° - \dfrac{∠ C}{2}

⇒ sec (A+B2)\Big(\dfrac{∠ A + ∠ B}{2}\Big) = sec (90°C2)\Big(90° - \dfrac{∠ C}{2}\Big)

⇒ sec (A+B2)\Big(\dfrac{∠ A + ∠ B}{2}\Big) = cosec C2\dfrac{∠ C}{2}

According to Assertion, sec (A+B2)=cosec ∠C\Big(\dfrac{∠ A + ∠ B}{2}\Big) = \text{cosec ∠C}cosec C2\text{cosec } \dfrac{∠ C}{2}

∴ Assertion (A) is false.

sec (90° - θ)=1cos (90° - θ)=1sin θ=cosec θ\text{sec (90° - θ)} = \dfrac{1}{\text{cos (90° - θ)}}\\[1em] = \dfrac{1}{\text{sin θ}}\\[1em] = \text{cosec θ}

∴ Reason (R) is true.

Hence, Assertion (A) is false, Reason (R) is true.

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