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Mathematics

a2 + b2 - c2 - d2 + 2ab - 2cd

Factorisation

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Answer

Given,

   a2 + b2 - c2 - d2 + 2ab - 2cd

= a2 + b2 + 2ab - c2 - d2 - 2cd

= (a + b)2 - (c2 + d2 + 2cd)

= (a + b)2 - (c + d)2

= (a + b + c + d)(a + b - c - d).

Hence, a2 + b2 - c2 - d2 + 2ab - 2cd = (a + b + c + d)(a + b - c - d).

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