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Mathematics

At what rate of interest per annum will a sum of ₹ 62500 earn a compound interest of ₹ 5100 in one year ? The interest is to be compounded half-yearly ?

Compound Interest

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Answer

Let rate of interest be r% per annum.

When interest is compounded half-yearly.

A=P(1+r2×100)n×2A = P\Big(1 + \dfrac{r}{2 \times 100}\Big)^{n \times 2}

Substituting values we get :

C.I.=APC.I.=P(1+r2×100)n×2P5100=62500×(1+r200)1×2625005100+62500=62500×(1+r200)267600=62500×(1+r200)26760062500=(1+r200)2676625=(1+r200)2(2625)2=(1+r200)21+r200=2625r200=26251r200=125r=20025=8%.\Rightarrow C.I. = A - P \\[1em] \Rightarrow C.I. = P\Big(1 + \dfrac{r}{2 \times 100}\Big)^{n \times 2} - P \\[1em] \Rightarrow 5100 = 62500 \times \Big(1 + \dfrac{r}{200}\Big)^{1 \times 2} - 62500 \\[1em] \Rightarrow 5100 + 62500 = 62500 \times \Big(1 + \dfrac{r}{200}\Big)^2 \\[1em] \Rightarrow 67600 = 62500 \times \Big(1 + \dfrac{r}{200}\Big)^2 \\[1em] \Rightarrow \dfrac{67600}{62500} = \Big(1 + \dfrac{r}{200}\Big)^2 \\[1em] \Rightarrow \dfrac{676}{625} = \Big(1 + \dfrac{r}{200}\Big)^2 \\[1em] \Rightarrow \Big(\dfrac{26}{25}\Big)^2 = \Big(1 + \dfrac{r}{200}\Big)^2 \\[1em] \Rightarrow 1 + \dfrac{r}{200} = \dfrac{26}{25} \\[1em] \Rightarrow \dfrac{r}{200} = \dfrac{26}{25}- 1 \\[1em] \Rightarrow \dfrac{r}{200} = \dfrac{1}{25} \\[1em] \Rightarrow r = \dfrac{200}{25} = 8\%.

Hence, rate of interest = 8%.

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