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Mathematics

In what time will ₹ 1500 yield ₹ 496.50 as compound interest at 20% per year compounded half-yearly ?

Compound Interest

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Answer

Given,

C.I. = ₹ 496.50

P = ₹ 1500

Rate = 20%

A = P + C.I. = ₹ 1500 + ₹ 496.50 = ₹ 1996.50

Let time required be n years.

When interest is compounded half-yearly.

A=P(1+r2×100)n×21996.50=1500×(1+20200)2n1996.501500=(1+20200)2n199650150000=(220200)2n13311000=(1110)2n(1110)3=(1110)2n2n=3n=32.\Rightarrow A = P\Big(1 + \dfrac{r}{2 \times 100}\Big)^{n \times 2} \\[1em] \Rightarrow 1996.50 = 1500 \times \Big(1 + \dfrac{20}{200}\Big)^{2n} \\[1em] \Rightarrow \dfrac{1996.50}{1500} = \Big(1 + \dfrac{20}{200}\Big)^{2n} \\[1em] \Rightarrow \dfrac{199650}{150000} = \Big(\dfrac{220}{200}\Big)^{2n} \\[1em] \Rightarrow \dfrac{1331}{1000} = \Big(\dfrac{11}{10}\Big)^{2n} \\[1em] \Rightarrow \Big(\dfrac{11}{10}\Big)^3 = \Big(\dfrac{11}{10}\Big)^{2n} \\[1em] \Rightarrow 2n = 3 \\[1em] \Rightarrow n = \dfrac{3}{2}.

Hence, required time = 1121\dfrac{1}{2} years.

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