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Chemistry

Atom Y has 2 electrons in its N shell, Atom X has 7 electrons in its M shell and atom Z has 6 protons in its neutral state.

Answer the following questions:

(a) Which atom is likely to form a cation ?

(b) What is the formula of the compound formed between X and Z?

(c) Draw the electron dot diagram of the compound of X and Y ?

(d) State 2 properties of the compound formed between X and Z

Chemical Bonding

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Answer

(a) Atom Y
Reason — Atom Y is most likely to form a cation, as it has only two electrons in its outermost shell. It will readily donate these two electrons to form a cation.

(b) Valency of X = 1
Valency of Z = 4

Z4+ X1−Z4 ↙↘ X1⇒Z1 ↙↘X4ZX4\text{Z}^{4+} \space \text{X}^{1-} \\[1em] \overset{{4}}{\text{Z}} \space {\swarrow}\mathllap{\searrow} \space \overset{1}{\text{X}} \Rightarrow \underset{1}{\text{Z}} \space {\swarrow}\mathllap{\searrow} \underset{4}{\text{X}} \\[1em] \text{Z}\text{X}_4

∴ The formula of the compound formed between X with valency 1 and Z with valency 4 will be ZX4.

(c)

Atom Y has 2 electrons in its N shell, Atom X has 7 electrons in its M shell and atom Z has 6 protons in its neutral state. Which atom is likely to form a cation ? (b) What is the formula of the compound formed between X and Z? (c) Draw the electron dot diagram of the compound of X and Y ? (d) State 2 properties of the compound formed between X and Z Model question paper 3 Solutions ICSE Class 10.

(d) Two properties of the compound formed between X and Z i.e, ZX4 are:

  1. It is a non-electrolyte as it contains no free ions or electrons to conduct electricity.
  2. It is a covalent compound having low melting and boiling point.

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