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A ball of mass m is dropped freely from point A. It is given that AB = BC = CD = h. If the acceleration due to gravity at the given place is g, then what will be its

(a) potential energy at point A?

(b) kinetic energy at point C?

A ball of mass m is dropped freely from point A. It is given that AB = BC = CD = h. If the acceleration due to gravity at the given place is g, then what will be its. Physics Competency Focused Practice Questions Class 10 Solutions.

Work, Energy & Power

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Answer

(a) Height of point A = 3h

So, potential energy PA = mg x 3h = 3mgh

(b) At point A, initial velocity = u = 0

At point C, final velocity = v

So, from third equation of motion:

v2 = u2 + 2g x 2h = u2 + 4gh

v2 = 4gh ……………(i)

Kinetic energy at C point, KC = 12mv2=12m×4gh=2mgh\dfrac{1}{2} \text m \text{v}^2 =\dfrac{1}{2} \text m \times 4\text{gh}= 2\text{mgh}

KC = 2mgh

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