Mathematics
If BM = DM then AM = CM :
yes
no
can't say
none of these
Triangles
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Answer
Given, BM = DM
⇒ M bisects line BD.
AB is parallel to CD.
In ΔABM and ΔCDM,
⇒ BM = DM
⇒ ∠MBA = ∠MDC (Alternate angles are equal)
⇒ ∠MAB = ∠MCD (Alternate angles are equal)
∴ ΔABM ≅ ΔCDM (By AAS congruency criterion)
By C.P.C.T.
⇒ AM = CM
Hence, option 1 is the correct option.
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