Chemistry
Calculate percentage of platinum in [(NH4)2 PtCl6]. Ammonium chloride platinate in nearest whole number.
Stoichiometry
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Answer
The relative molecular mass of (NH4)2 PtCl6
= 2(14 + 4 x 1) + 195 + 6 x 35.5
= 36 + 195 + 213
= 444 amu
Wt. of Pt in [(NH4)2 PtCl6] = 195 g
∴ Percentage of platinum in (NH4)2PtCl6 is
= x 100
= 43.91 %
∴ Rounding to the nearest whole number, the percentage of platinum in ammonium chloride platinate (NH4)2 PtCl6 is 44%.
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