Calculate the mass of iron in 10 kg of iron ore which contains 80% of pure ferric oxide.
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Question

Calculate the mass of iron in 10 kg of iron ore which contains 80% of pure ferric oxide.

KnowledgeBoat · Accepted Answer

Atomic wt. of Fe = 56 and O = 16 Molecular mass of Fe₂O₃ = 2Fe + 3O =(2 x 56) + (3 x 16) = 112 + 48 = 160 g Iron present in 80% of Fe₂O₃ = x 80 = 56 g ∴ Mass of iron in 100 g of iron ore = 56 g Hence, mass of iron present in 10 kg (i.e., 10,000 g) of iron ore = x 10000 = 5600 g = 5.6 kg

Chemistry

Calculate the mass of iron in 10 kg of iron ore which contains 80% of pure ferric oxide.

Mole Concept

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Chemistry

Calculate the mass of iron in 10 kg of iron ore which contains 80% of pure ferric oxide.

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