Chemistry
Calculate the percentage of phosphorus in
(a) Calcium hydrogen phosphate Ca(H2PO4)2
(b) Calcium phosphate Ca3(PO4)2
Mole Concept
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Answer
(a) Molecular mass of Ca(H2PO4)2
= Ca + 2[2H + P + 4O]
= 40 + 2[2(1) + 31 + 4(16)]
= 40 + 2[2 + 31 + 64]
= 40 + 194
= 234
234 g of Ca(H2PO4)2 contains 62 g of P
∴ 100 g of Ca(H2PO4)2 contains
= x 100 = 26.5%
(b) Molecular mass of Ca3(PO4)2
= 3Ca + 2[P + 4O]
= (3 x 40) + 2[31 + 4(16)]
= 120 + 2[31 + 64]
= 120 + 190
= 310
310 g of Ca3(PO4)2 contains 62 g of P
∴ 100 g of Ca3(PO4)2 contains
= x 100 = 20 %
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