Calculate the relative molecular mass [molecular weight] of 290 ml. of a gas 'A' at 17 °C and 1520 mm pressure which weighs 2.73 g at s.t.p. [1 litre of hydrogen at s.t.p. weighs 0.09 g.]
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Question

Calculate the relative molecular mass [molecular weight] of 290 ml. of a gas 'A' at 17 °C and 1520 mm pressure which weighs 2.73 g at s.t.p. [1 litre of hydrogen at s.t.p. weighs 0.09 g.]

KnowledgeBoat · Accepted Answer

Convert the volume to s.t.p. using gas equation Initial Conditions | Final Conditions (s.t.p.) -------------------|-------------------------- P₁ = 1520 mm of Hg | P₂ = 760 mm of Hg V₁ = 290 ml | V₂ = x lit T₁ = 17 + 273 K | T₂ = 273 K Using the gas equation, Substituting the values we get, 546 ml of gas at s.t.p. weighs 2.73 g Wt. of 1000 ml of gas = Vapour density of gas X = Hence, vapour density of gas is 55.55 Molecular weight = 2 x Vapour Density = 2 x 55.555 = 111.11 g Hence, molecular weight of gas is 111.11 g

Chemistry

Calculate the relative molecular mass [molecular weight] of 290 ml. of a gas 'A' at 17 °C and 1520 mm pressure which weighs 2.73 g at s.t.p. [1 litre of hydrogen at s.t.p. weighs 0.09 g.]

Mole Concept

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Chemistry

Calculate the relative molecular mass [molecular weight] of 290 ml. of a gas 'A' at 17 °C and 1520 mm pressure which weighs 2.73 g at s.t.p. [1 litre of hydrogen at s.t.p. weighs 0.09 g.]

Mole Concept

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