Chemistry
State the volume occupied by 40 g of a hydrocarbon – CH4 at s.t.p. if it's V.D. is 8.
Mole Concept
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Answer
Vapour density of hydrocarbon = 8
∴ Molecular weight = 2 x Vapour density
= 2 x 8 = 16 g
16 g of hydrocarbon at s.t.p. occupy 22.4 lit
∴ 40 g of hydrocarbon will occupy =
Hence, volume occupied by 40 g of a hydrocarbon (CH4) at s.t.p. is 56 lit.
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