Physics

Calculate the total amount of heat energy required to convert 100 g of ice at -10° C completely into water at 100° C. Specific heat capacity of ice = 2.1 J g-1 K-1, specific heat capacity of water = 4.2 J g-1 K-1, specific latent heat of ice = 336 J g-1.

Calorimetry

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Answer

Given,

m = 100 g

Specific heat capacity of ice = 2.1 J g-1 K-1

specific heat capacity of water = 4.2 J g-1 K-1

specific latent heat of ice = 336 J g-1

total amount of heat energy required = ?

Heat energy taken by ice to raise it's temperature from at –10° C to 0° C
= m x c x change in temperature
= 100 × 2.1 × [0 - (-10)]
= 100 x 2.1 x 10
= 2100 J

Heat energy taken by ice at 0° C to convert into water at 0° C
= m x L
= 100 × 336
= 33600 J

Heat energy taken by water to raise the temperature from 0° C to 100° C
= m x c x change in temperature
= 100 × 4.2 × (100 - 0)
= 100 × 4.2 × 100
= 42000 J

Total heat energy gained is
= 2100 + 33600 + 42000
= 77700 J
= 7.77 × 104 J

Hence, total amount of heat energy required = 7.77 × 104 J

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