Calculate the volume occupied by 3.5 g of O₂ gas at 27 °C and 740 mm pressure. [O = 16]
Mole Concept
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Question

Calculate the volume occupied by 3.5 g of O₂ gas at 27 °C and 740 mm pressure. [O = 16]

KnowledgeBoat · Accepted Answer

Gram molecular mass of O₂ = 2 x 16 = 32 g 1 mole of O₂ weighs 32 g and occupies 22.4 lit. vol. 3.5 g of O₂ occupies = Volume occupied by 3.5 g of O₂ gas at 27°C and 740 mm pressure: s.t.p. | given values --------|-------------------------- P₁ = 760 mm of Hg | P₂ = 740 mm of Hg V₁ = 2.45 lit | V₂ = x lit T₁ = 273 K | T₂ = 27 + 273 K Using the gas equation, Substituting the values we get, Hence, the volume occupied by 3.5 g of O₂ gas at 27°C and 740 mm pressure is 2.76 lit.

Chemistry

Calculate the volume occupied by 3.5 g of O₂ gas at 27 °C and 740 mm pressure. [O = 16]

Mole Concept

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