Calculate the volume occupied by 3.5 g of O 2 gas at 27 °C and 740 mm pressure. [O = 16]

Gram molecular mass of O 2 = 2 x 16 = 32 g 1 mole of O 2 weighs 32 g and occupies 22.4 lit. vol. 3.5 g of O 2 occupies = Volume occupied by 3.5 g of O 2 gas at 27°C and 740 mm pressure: s.t.p. | given values --------|-------------------------- P 1 = 760 mm of Hg | P 2 = 740 mm of Hg V 1 = 2.45 lit | V 2 = x lit T 1 = 273 K | T 2 = 27 + 273 K Using the gas equation, Substituting the values we get, Hence, the volume occupied by 3.5 g of O 2 gas at 27°C and 740 mm pressure is 2.76 lit.

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