Science
Choose the correct option from the below which explains the reason for us to perceive the day sky as blue.
options
- As sunlight passes through the atmosphere, shorter wavelengths, such as blue are scattered more than other colors.
- The sky appears blue because all colors are scattered equally, but blue light is stronger and more visible to the human eye.
- The blue color of the sky is due to longer wavelengths like red and orange scattering more than shorter wavelengths, making blue stand out more.
- The atmosphere contains blue-colored particles that give the sky its blue appearance.
Answer
As sunlight passes through the atmosphere, shorter wavelengths, such as blue are scattered more than other colors.
Reason — When sunlight enters the Earth’s atmosphere, it interacts with tiny air molecules and dust particles which is known as Rayleigh scattering.
The amount of scattering is inversely proportional to the fourth power of the wavelength, meaning shorter wavelengths (like blue and violet) are scattered much more than longer wavelengths (like red and yellow).
Although violet light is scattered even more than blue, our eyes are more sensitive to blue light.
Therefore, the sky appears blue to us during the day due to difference in scattering amount for different colours (wavelengths).
Related Questions
Oxygen can combine with both metals and non-metals. It combines with Calcium to form CaO and with carbon to form CO2.
(a) What type of bond is formed between carbon and oxygen?
(b) Identify the type of bond formed between Calcium and oxygen.
(c) Which of the above compounds will be a good conductor of electricity in molten state and why?
(d) Comment on the physical state (solid, liquid or gas) of CaO and CO2.
(e) What is the valency of carbon in CO2?
The below image shows the formation of an image with an optical instrument.

(a) Identify the optical instrument (shown schematically as a rectangle) in the image.
(b) What type of image is formed in this case?
(c) Based on the measurements given in the image, calculate the focal length of the instrument.