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Chemistry

Compound A is bubbled through bromine dissolved in carbon tetrachloride and the product formed is CH2Br–CH2Br.

(i) Draw the structural formula of A.

(ii) What type of reaction has A undergone.

(iii) What is your observation.

(iv) Name (not formula) the compound formed when steam reacts with A in the presence of phosphoric acid.

(v) What is the procedure for converting the product of (e) (iv) back to A ?

Organic Chemistry

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Answer

(i) Compound A is Ethene (H2C=CH2). It's structural formula is shown below:

Compound X is bubbled through bromine dissolved in CCl<sub>4</sub> and the product formed is CH2Br – CH2Br. Draw the structural formula of X and state what type of reaction X has undergone. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10

(ii) Ethene [CH2=CH2] has undergone addition reaction.

(iii) Brown colour of bromine is discharged.

(iv) Ethanol

C2H4Ethene+H2O waterH+acidC2H5OH ethanol\underset{\text{Ethene}}{\text{C}2\text{H}4} + \underset{\text{ water} }{\text{H}2\text{O}} \underset{\text{acid}}{\xrightarrow{\text{H}}^+} \underset{\text{ ethanol} }{\text{C}2\text{H}_5\text{OH}}

(v) Ethanol can be converted into ethene, by dehydrating it with concentrated H2SO4 at 170°C.

C2H5OH ethyl alcohol170°CConc. H2SO4[excess]C2H4ethene+H2O\underset{\text{ ethyl alcohol}}{\text{C}2\text{H}5\text{OH}} \xrightarrow[170\degree\text{C}]{\text{Conc. H}2\text{SO}4\text{[excess]}} \underset{ \text{ethene}}{\text{C}2\text{H}4} + \text{H}_2\text{O}\

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