If P = sum lent, r = rate of interest per year, n = number of years and amounts =A, then :

1. $A = P\Big(1 + \dfrac{r}{100}\Big)^n$

2. $A - P = \Big(1 + \dfrac{r}{100}\Big)^n$

3. $A = P\Big(1 - \dfrac{r}{100}\Big)^n$

4. A - P = $\Big(1 - \dfrac{r}{100}\Big)^n$

If the letters used have usual meanings : r₁% and r₂% are rate of interests for two consecutive years then :

1. $A = P\Big(1 + \dfrac{r$1}{100}\Big)\Big(1 - \dfrac{r2}{100}\Big)

2. $A = P\Big(1 + \dfrac{r$1}{100}\Big)\Big(1 + \dfrac{r2}{100}\Big)

3. $A - P = \Big(1 + \dfrac{r$1}{100}\Big)\Big(1 + \dfrac{r2}{100}\Big)

4. $P = A\Big(1 - \dfrac{r$1}{100}\Big)\Big(1 - \dfrac{r2}{100}\Big)

A sum of money, lent out at 10% C.I. compounded yearly becomes ₹ 6050 in 2 years. The sum lent is :

1. ₹ 7260

2. ₹ 4000

3. ₹ 5000

4. ₹ 7320.50

On a certain sum, the compound interest accrued in one year is ₹ 550. If the rate of interest is 10%, the sum is :

1. ₹ 5000

2. ₹ 6000

3. ₹ 4500

4. ₹ 5500