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Mathematics

If the letters used have usual meanings : r1% and r2% are rate of interests for two consecutive years then :

  1. A=P(1+r1100)(1−r2100)A = P\Big(1 + \dfrac{r1}{100}\Big)\Big(1 - \dfrac{r2}{100}\Big)

  2. A=P(1+r1100)(1+r2100)A = P\Big(1 + \dfrac{r1}{100}\Big)\Big(1 + \dfrac{r2}{100}\Big)

  3. A−P=(1+r1100)(1+r2100)A - P = \Big(1 + \dfrac{r1}{100}\Big)\Big(1 + \dfrac{r2}{100}\Big)

  4. P=A(1−r1100)(1−r2100)P = A\Big(1 - \dfrac{r1}{100}\Big)\Big(1 - \dfrac{r2}{100}\Big)

Compound Interest

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Answer

If the letters used have usual meanings : r1% and r2% are rate of interests for two consecutive years then :

A=P(1+r1100)(1+r2100)A = P\Big(1 + \dfrac{r1}{100}\Big)\Big(1 + \dfrac{r2}{100}\Big)

Hence, Option 2 is the correct option.

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