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Mathematics

Compute:

(29÷211)3(2^{-9} ÷ 2^{-11})^3

Exponents

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Answer

According to quotient property,

am÷an=amna^m ÷ a^n = a^{m - n}

(29÷211)3=(29(11))3=(29+11)3=(22)3=(2)2×3=26=2×2×2×2×2×2=64(2^{-9} ÷ 2^{-11})^3\\[1em] = (2^{-9 - (-11)})^3\\[1em] = (2^{-9 + 11})^3\\[1em] = (2^{2})^3\\[1em] = (2)^{2\times3}\\[1em] = 2^{6}\\[1em] = 2 \times 2 \times 2 \times 2 \times 2 \times 2\\[1em] = 64

Hence, (29÷211)3=64(2^{-9} ÷ 2^{-11})^3 = 64

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