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Mathematics

Consider this puzzle: What is the square root of –1? We know that 1×1=11 \times 1 = 1. We also know that (1)×(1)=1(-1) \times (-1) = 1. There is no Real Number that, when multiplied by itself, results in a negative number. Thus, 1\sqrt{-1} cannot exist on number line.

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Answer

It is true that 1\sqrt{-1} cannot exist on the real number line.

Reason :

By Brahmagupta's laws :

⇒ A positive number multiplied by a positive number gives a positive number : (+) × (+) = (+).

⇒ A negative number multiplied by a negative number gives a positive number : (-) × (-) = (+).

So, the square of any real number (positive, negative or zero) is always non-negative. There is no real number whose square is -1.

Hence, 1\sqrt{-1} has no place on the real number line.

To handle expressions like 1\sqrt{-1}, mathematicians invented a new kind of number called the Imaginary Unit, denoted by i, where :

⇒ i2 = -1

⇒ i = 1\sqrt{-1}.

This led to the development of Imaginary Numbers, which extend the real number line into a new dimension and form the basis of Complex Numbers (numbers of the form a + bi, where a and b are real numbers).

Imaginary numbers are essential in modern electrical engineering, quantum mechanics, signal processing and several other fields.

Hence, 1\sqrt{-1} does not exist on the real number line; it is denoted by i, the imaginary unit, which forms the foundation of complex numbers.

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