If cot θ = 1; find the value of : 5 tan2θ + 2 sin2θ - 3

Question

KnowledgeBoat · Accepted Answer

Given: cot θ = 1 ∴ If length of AB = x unit, length of BC = x unit. In Δ ABC, ⇒ AC2 = BC2 \+ AB2 (∵ AC is hypotenuse) ⇒ AC2 = (x)2 \+ (x)2 ⇒ AC2 = x2 \+ x2 ⇒ AC2 = 2x2 ⇒ AC = ⇒ AC = x sin θ = tan θ = Now, 5 tan2 θ + 2 sin2 θ - 3 Hence, 5 tan2θ + 2 sin2θ - 3 = 3.

Mathematics

If cot θ = 1; find the value of :
5 tan²θ + 2 sin²θ - 3

Trigonometric Identities

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