Physics
The above diagram shows a glass prism of a critical angle 42°.
(a) Redraw the diagram and complete the path of the light ray PQ till it emerges out of the prism.
(b) Also, calculate the net angle of deviation of the ray PQ when it emerges from the prism.
Refraction Plane Surfaces
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Answer
(a) Below diagram shows the completed path of light ray PQ till it emerges out of the prism:
(b) In △APX
∠A = 48° and ∠APX = 90°
So,
∠AXP = 180° - (48° + 90°) = 42°
∠PXN = 90° - 42° = 48°
∠PXN = ∠XYB = 48° (∵ Corresponding angles)
Angle of deviation of the ray PQ = ∠ D = 180°- 48° = 132°
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