Chemistry
Dilute and concentrated sulphuric acid can be distinguished by using metals copper and zinc. Explain by giving balanced equations.
Sulphuric Acid
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Answer
Conc. sulphuric acid acts as an oxidising agent and oxidises metals like copper and Zinc.
Cu + 2H2SO4 (conc.) ⟶ CuSO4 + H2O + 2SO2 ↑
Zn + 2H2SO4 (conc.) ⟶ ZnSO4 + H2O + 2SO2 ↑
Whereas, dil. sulphuric acid is not an oxidising agent and it cannot oxidise copper and zinc.
Hence, Conc. sulphuric acid and dil. sulphuric acid can be distinguished by considering the oxidising property of sulphuric acid.
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Related Questions
Give balanced equation(s) for :
(a) Reaction of dilute sulphuric acid when poured over sodium sulphite
(b) Manufacture of sulphuric acid by the Contact process.
(c) Heating sulphur with conc. sulphuric acid
(d) Dehydration of sugar crystals by conc. sulphuric acid
(e) Action of concentrated sulphuric acid on carbon.
Write the equations for the following reactions:
(a) dil. H2SO4 and barium chloride.
(b) dil. H2SO4 and sodium sulphide.
(c) Zinc sulphide and dilute sulphuric acid.
Give two balanced reactions of each type to show the following properties of sulphuric acid:
(a) Acidic nature
(b) Oxidising agent
(c) Dehydrating Nature
(d) Non-volatile nature
Give a chemical test to distinguish between:
(a) dilute sulphuric acid and dilute hydrochloric acid (using lead nitrate solution).
(b) dilute sulphuric acid and concentrated sulphuric acid.
(c) Dilute sulphuric acid and dilute hydrochloric acid [using barium chloride solution]