Chemistry

Divide the following redox reactions into oxidation and reduction half reactions.

(i) Zn + Pb2+ ⟶ Zn2+ + Pb

(ii) Zn + Cu2+ ⟶ Zn2+ + Cu

(iii) Cl2 + 2Br- ⟶ Br2 + 2Cl-

Hydrogen

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Answer

(i) Zn + Pb2+ ⟶ Zn2+ + Pb

Oxidation : Zn ⟶ Zn2+ + 2e-

Reduction : Pb2+ + 2e- ⟶ Pb

(ii) Zn + Cu2+ ⟶ Zn2+ + Cu

Oxidation : Zn ⟶ Zn2+ + 2e-

Reduction : Cu2+ + 2e- ⟶ Cu

(iii) Cl2 + 2Br- ⟶ Br2 + 2Cl-

Oxidation : Cl2 ⟶ 2Cl- + 2e-

Reduction : 2Br- + 2e- ⟶ Br2

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