Draw a ΔABC in which BC = 5.6 cm, ∠B = 45° and the median AD from A to BC is 4.5 cm. Inscribe a circle in it.

Steps of construction :

1. Draw a line segment BC = 5.6 cm.

2. Construct perpendicular bisector of BC which intersect BC at D.

3. At B, construct angle ∠XBC = 45°.

4. From D, with radius 4.5 cm draw an arc that intersect BX, mark it as A.

5. Join AB and AC. Hence, ABC is the required triangle.

6. Construct the angle bisector BH and CI of ∠ABC and ∠ACB respectively.

7. Let the two angle bisectors intersect at point O.

8. Draw OP perpendicular to BC. With O as centre and OP as radius, draw a circle.