Draw the graph for each equation, given below :
(i) x = 5
(ii) x + 5 = 0
(iii) y = 7
(iv) y + 7 = 0
(v) 2x + 3y = 0
(vi) 3x + 2y = 6
(vii) x - 5y + 4 = 0
(viii) 5x + y + 5 = 0

Question

Draw the graph for each equation, given below : (i) x = 5 (ii) x + 5 = 0 (iii) y = 7 (iv) y + 7 = 0 (v) 2x + 3y = 0 (vi) 3x + 2y = 6 (vii) x - 5y + 4 = 0 (viii) 5x + y + 5 = 0

KnowledgeBoat · Accepted Answer

(i) x = 5 (ii) x + 5 = 0 x = -5 (iii) y = 7 (iv) y + 7 = 0 y = -7 (v) 2x + 3y = 0 Step 1: Give at least three suitable values to the variable x and find the corresponding values of y. Let x = -1, then 2 (-1) + 3y = 0 ⇒ y = 0.6 Let x = 0, then 2 0 + 3y = 0 ⇒ y = 0 Let x = 1, then 2 1 + 3y = 0 ⇒ y = - 0.6 Step 2: Make a table (as given below) for the different pairs of the values of x and y: x | -1 | 0 | 1 --|--- |---|--- y | 0.6| 0 | -0.6 Step 3: Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph. (vi) 3x + 2y = 6 Step 1: Give at least three suitable values to the variable x and find the corresponding values of y. Let x = -1, then 3 (-1) + 2y = 6 ⇒ y = 4.5 Let x = 0, then 3 0 + 2y = 6 ⇒ y = 3 Let x = 1, then 3 1 + 2y = 6 ⇒ y = 1.5 Step 2: Make a table (as given below) for the different pairs of the values of x and y: x | -1 | 0 | 1 --|--- |---|--- y | 4.5| 3 | 1.5 Step 3: Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph. (vii) x - 5y + 4 = 0 Step 1: Give at least three suitable values to the variable x and find the corresponding values of y. Let x = -2, then (-2) - 5y + 4 = 0 ⇒ y = 0.4 Let x = 0, then 0 - 5y + 4 = 0 ⇒ y = 0.8 Let x = 2, then 2 - 5y + 4 = 0 ⇒ y = 1.2 Step 2: Make a table (as given below) for the different pairs of the values of x and y: x | -2 | 0 | 2 --|--- |---|--- y | 0.4|0.8|1.2 Step 3: Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph. (viii) 5x + y + 5 = 0 Step 1: Give at least three suitable values to the variable x and find the corresponding values of y. Let x = -1, then 5 (-1) + y + 5 = 0 ⇒ y = 0 Let x = 0, then 5 0 + y + 5 = 0 ⇒ y = -5 Let x = 1, then 5 1 + y + 5 = 0 ⇒ y = -10 Step 2: Make a table (as given below) for the different pairs of the values of x and y: x | -1| 0 | 1 --|---|---|--- y | 0 |-5 | -10 Step 3: Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Mathematics

Draw the graph for each equation, given below :
(i) x = 5
(ii) x + 5 = 0
(iii) y = 7
(iv) y + 7 = 0
(v) 2x + 3y = 0
(vi) 3x + 2y = 6
(vii) x - 5y + 4 = 0
(viii) 5x + y + 5 = 0

Graphical Solution

Related Questions

The line 5x - 4y - 20 = 0 intersects y-axis at point A. The co-ordinates of point A are :
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(5, 0)
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x-axis
y-axis
x-axis or y-axis
x-axis and y-axis both

Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0
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Mathematics

Draw the graph for each equation, given below :(i) x = 5(ii) x + 5 = 0(iii) y = 7(iv) y + 7 = 0(v) 2x + 3y = 0(vi) 3x + 2y = 6(vii) x - 5y + 4 = 0(viii) 5x + y + 5 = 0

Graphical Solution

Related Questions

The line 5x - 4y - 20 = 0 intersects y-axis at point A. The co-ordinates of point A are :(-5, 0)(5, 0)(0, 5)(0, -5)

The point (0, 0) lies on :x-axisy-axisx-axis or y-axisx-axis and y-axis both

Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0Calculate the area of the triangle formed by the line drawn and the co-ordinate axes.

Draw the graph for each equation, given below :
(i) x = 5
(ii) x + 5 = 0
(iii) y = 7
(iv) y + 7 = 0
(v) 2x + 3y = 0
(vi) 3x + 2y = 6
(vii) x - 5y + 4 = 0
(viii) 5x + y + 5 = 0

The line 5x - 4y - 20 = 0 intersects y-axis at point A. The co-ordinates of point A are :
(-5, 0)
(5, 0)
(0, 5)
(0, -5)

The point (0, 0) lies on :
x-axis
y-axis
x-axis or y-axis
x-axis and y-axis both

Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0
Calculate the area of the triangle formed by the line drawn and the co-ordinate axes.