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Mathematics

Draw a histogram for the following distribution :

Marks out of 80No. of students
40-442
45-498
50-5412
55-5910
60-648

Hence, estimate the mode.

Statistics

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Answer

By formula,

Adjustment factor =

Lower limit of a class - Upper limit of preceding class2=45442=12\dfrac{\text{Lower limit of a class - Upper limit of preceding class}}{2} = \dfrac{45 - 44}{2} = \dfrac{1}{2} = 0.5

New lower class limit = Lower class limit - Adjustment factor

New upper class limit = Upper class limit + Adjustment factor

Marks out of 80 (Class-interval)New class-intervalNo. of students
40-4439.5-44.52
45-4944.5-49.58
50-5449.5-54.512
55-5954.5-59.510
60-6459.5-64.58

Steps of construction :

  1. Draw a histogram of the given distribution.

  2. Inside the highest rectangle, which represents the maximum frequency (or modal class), draw two lines AC and BD diagonally from the upper corners C and D of adjacent rectangles.

  3. Through the point E (the point of intersection of diagonals AC and BD), draw EF perpendicular to the horizontal axis.

  4. The value of point F on the horizontal axis represents the value of mode.

Draw a histogram for the following distribution : Model Question Paper - 1, Concise Mathematics Solutions ICSE Class 10.

From graph,

F = 52.75

Hence, required mode = 52.75.

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