If x² + $\dfrac{1}{\text{x}^2}$ = 3, the value of x - $\dfrac{1}{\text{x}}$ is:

1. 1

2. -1

3. $\pm 1$

4. 0

If a³ + b³ + c³ = 3abc, then a + b + c is equal to:

1. 1

2. -1

3. $\pm 1$

4. 0

If a = x + $\dfrac{1}{\text{x}}$ and b = x - $\dfrac{1}{\text{x}}$, then a² - b² is:

1. x² + $\dfrac{1}{\text{x}^2}$

2. x² - $\dfrac{1}{\text{x}^2}$

3. 4

4. $2\Big(x^2 + \dfrac{1}{\text{x}^2}\Big)$

Statement 1: x > 0 and $x^2 + \dfrac{1}{x^2}$ = 2, then $x^2 - \dfrac{1}{x^2}$ = 0

Statement 2: $(x + \dfrac{1}{x})^2 = x^2 + \dfrac{1}{x^2} + 2$ = 2 + 2 = 4

$(x - \dfrac{1}{x})^2 = x^2 + \dfrac{1}{x^2} - 2$ = 2 - 2 = 0

and, $(x^2 - \dfrac{1}{x^2}) = (x + \dfrac{1}{x})(x - \dfrac{1}{x})$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.