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Mathematics

For equation x3y2\dfrac{x}{3}-\dfrac{y}{2} = 1, the value of y for x = 9 is :

  1. -4

  2. 6

  3. 4

  4. -6

Coordinate Geometry

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Answer

Given:

x3y2=1\dfrac{x}{3} - \dfrac{y}{2} = 1

When x = 9,

93y2=13y2=131=y22=y2y=2×2y=4⇒ \dfrac{9}{3} - \dfrac{y}{2} = 1\\[1em] ⇒ 3 - \dfrac{y}{2} = 1\\[1em] ⇒ 3 - 1 = \dfrac{y}{2}\\[1em] ⇒ 2 = \dfrac{y}{2}\\[1em] ⇒ y = 2 \times 2\\[1em] ⇒ y = 4

Hence, option 3 is the correct option.

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