Mathematics
Equation 2x2 - 3x + 1 = 0 has :
distinct and real roots
no real roots
equal roots
imaginary roots
Answer
Comparing equation 2x2 - 3x + 1 = 0, with ax2 + bx + c = 0, we get :
a = 2, b = -3 and c = 1.
By formula,
D = b2 - 4ac
= (-3)2 - 4 × 2 × 1
= 9 - 8
= 1; which is positive.
Since, a, b and c are real numbers; a ≠ 0 and b2 - 4ac > 0
∴ Roots are real and unequal.
Hence, Option 1 is the correct option.
Related Questions
Solve for x using the quadratic formula. Write your answer correct to two significant figures.
(x - 1)2 - 3x + 4 = 0
x = 3 is a solution of the quadratic equation (k + 2)x2 - kx + 6 = 0, then other root is :
-1
3
-3
-4
Which of the following equations has two real and distinct roots ?
x2 - 5x + 6 = 0
x2 - 3x + 6 = 0
x2 - 2x + 5 = 0
x2 - 4x + 6 = 0
If the roots of equation x2 - 6x + k = 0 are real and distinct, then value of k is :
> -9
> -6
< 6
< 9