If the equation, ax2 + 2x + a = 0 has two real and equal roots, then: 1. a = 0, 1 2. a = 1, 1 3. a = 0, -1 4. a = -1, 1

Comparing ax2 + 2x + a = 0 with ax2 + bx + c = 0 we get, a = a, b = 2 and c = a. We know that, Since equations has real and equal roots, ⇒ D = 0 ⇒ b2 - 4ac = 0 ⇒ (2)2 - 4(a)(a) = 0 ⇒ 4 - 4a2 = 0 ⇒ 4 = 4a2 ⇒ a2 = ⇒ a2 = 1 ⇒ a = ⇒ a = 1 ⇒ a = -1, 1. Hence, option 4 is the correct option.