Mathematics
If the equation, ax2 + 2x + a = 0 has two real and equal roots, then:
a = 0, 1
a = 1, 1
a = 0, -1
a = -1, 1
Quadratic Equations
1 Like
Answer
Comparing ax2 + 2x + a = 0 with ax2 + bx + c = 0 we get,
a = a, b = 2 and c = a.
We know that,
Since equations has real and equal roots,
⇒ D = 0
⇒ b2 - 4ac = 0
⇒ (2)2 - 4(a)(a) = 0
⇒ 4 - 4a2 = 0
⇒ 4 = 4a2
⇒ a2 =
⇒ a2 = 1
⇒ a =
⇒ a = ± 1
⇒ a = -1, 1.
Hence, option 4 is the correct option.
Answered By
1 Like
Related Questions
The nature of the roots of the equation, 3x2 - + 4 = 0 is:
real and equal
irrational and unequal
rational and unequal
imaginary and unequal
The value of the discriminant of the equation 2x2 - 3x + 5 = 0, is:
31
-31
The value of the discriminant of the equation, = 0 is:
4
16
-16
-12
The value of the discriminant of the equation, x2 - ( + 1)x + = 0 is:
3 +
1 -
3 -
2 -