The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0

Question

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is: 1. x – 3y + 1 = 0 2. 3x + y + 1 = 0 3. 3x – y – 1 = 0 4. 3x – y + 1 = 0

KnowledgeBoat · Accepted Answer

The given line is , so its slope is m = 3. Since the required line is parallel, its slope is also m = 3. Using the point-slope form y - y1 = m(x - x1) with the point (x1, y1) = (1, 2) and m=3: y - 2 = 3(x - 1) y - 2 = 3x - 3 Rearranging the equation to the standard form (Ax + By + C = 0): 0 = 3x - y - 3 + 2 3x - y - 1 = 0 Hence, option 3 is the correct option.

Mathematics

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0

Straight Line Eq

Related Questions

Mathematics

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:x – 3y + 1 = 03x + y + 1 = 03x – y – 1 = 03x – y + 1 = 0

Straight Line Eq

Related Questions

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0