Given,
⇒[cos45°2cos0°sin30°sin0°][sin45°sin90°cos90°cot45°]⇒212(1)21021101⇒21221021101⇒21×21+21×12×21+0×121×0+21×12×0+0×1⇒[21+211+00+210+0]⇒[11210]⇒[110.50]
Hence, [cos45°2cos0°sin30°sin0°][sin45°sin90°cos90°cot45°]=[110.50].