KnowledgeBoat Logo
|

Mathematics

Find x and y if : [x3xy4y][21]=[512]\begin{bmatrix}[r] x & 3x \ y & 4y \end{bmatrix}\begin{bmatrix}[r] 2 \ 1 \end{bmatrix} = \begin{bmatrix}[r] 5 \ 12 \end{bmatrix}.

Matrices

12 Likes

Answer

[x3xy4y][21]=[512][x×2+3x×1y×2+4y×1]=[512][5x6y]=[512]\Rightarrow \begin{bmatrix}[r] x & 3x \ y & 4y \end{bmatrix}\begin{bmatrix}[r] 2 \ 1 \end{bmatrix} = \begin{bmatrix}[r] 5 \ 12 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] x \times 2 + 3x \times 1 \ y \times 2 + 4y \times 1 \end{bmatrix}= \begin{bmatrix}[r] 5 \ 12 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 5x \ 6y \end{bmatrix}= \begin{bmatrix}[r] 5 \ 12 \end{bmatrix} \\[1em]

By definition of equality of matrices we get,

5x = 5
⇒ x = 1.

6y = 12
⇒ y = 2.

Hence, x = 1 and y = 2.

Answered By

5 Likes


Related Questions