Evaluate :
70×(25)−32−5−37^0 \times (25)^{-\dfrac{3}{2}} - 5^{-3}70×(25)−23−5−3
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Simplifying the expression :
⇒70×(25)−32−5−3=1×(52)−32−5−3=1×5−3−5−3=5−3−5−3=0.\Rightarrow 7^0 \times (25)^{-\dfrac{3}{2}} - 5^{-3} = 1 \times (5^2)^{-\dfrac{3}{2}} - 5^{-3} \\[1em] = 1 \times 5^{-3} - 5^{-3} \\[1em] = 5^{-3} - 5^{-3} \\[1em] = 0.⇒70×(25)−23−5−3=1×(52)−23−5−3=1×5−3−5−3=5−3−5−3=0.
Hence, 70×(25)−32−5−3=0.7^0 \times (25)^{-\dfrac{3}{2}} - 5^{-3} = 0.70×(25)−23−5−3=0.
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5−4×(125)53÷(25)−125^{-4} \times (125)^{\dfrac{5}{3}} ÷ (25)^{-\dfrac{1}{2}}5−4×(125)35÷(25)−21
(27125)23×(925)−32\Big(\dfrac{27}{125}\Big)^{\dfrac{2}{3}} \times \Big(\dfrac{9}{25}\Big)^{-\dfrac{3}{2}}(12527)32×(259)−23
(1681)−34×(499)32÷(343216)23\Big(\dfrac{16}{81}\Big)^{-\dfrac{3}{4}} \times \Big(\dfrac{49}{9}\Big)^{\dfrac{3}{2}} ÷ \Big(\dfrac{343}{216}\Big)^{\dfrac{2}{3}}(8116)−43×(949)23÷(216343)32
Simplify :
(8x3÷125y3)23(8x^3 ÷ 125y^3)^{\dfrac{2}{3}}(8x3÷125y3)32
