Evaluate :
5−4×(125)53÷(25)−125^{-4} \times (125)^{\dfrac{5}{3}} ÷ (25)^{-\dfrac{1}{2}}5−4×(125)35÷(25)−21
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Simplifying the expression :
⇒5−4×(125)53÷(25)−12=5−4×(53)53÷(52)−12=5−4×55÷5−1=5−4×55÷15=5−4×55×51=5−4+5+1=52=25.\Rightarrow 5^{-4} \times (125)^{\dfrac{5}{3}} ÷ (25)^{-\dfrac{1}{2}} = 5^{-4} \times (5^3)^{\dfrac{5}{3}} ÷ (5^2)^{-\dfrac{1}{2}} \\[1em] = 5^{-4} \times 5^5 ÷ 5^{-1} = 5^{-4} \times 5^5 ÷ \dfrac{1}{5} \\[1em] = 5^{-4} \times 5^5 \times 5^1 \\[1em] = 5^{-4 + 5 + 1} = 5^2 \\[1em] = 25.⇒5−4×(125)35÷(25)−21=5−4×(53)35÷(52)−21=5−4×55÷5−1=5−4×55÷51=5−4×55×51=5−4+5+1=52=25.
Hence, 5−4×(125)53÷(25)−12=25.5^{-4} \times (125)^{\dfrac{5}{3}} ÷ (25)^{-\dfrac{1}{2}} = 25.5−4×(125)35÷(25)−21=25.
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3×(32)25×703 \times (32)^{\dfrac{2}{5}} \times 7^03×(32)52×70 is equal to :
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33×(243)−23×(9)−133^3 \times (243)^{-\dfrac{2}{3}} \times (9)^{-\dfrac{1}{3}}33×(243)−32×(9)−31
(27125)23×(925)−32\Big(\dfrac{27}{125}\Big)^{\dfrac{2}{3}} \times \Big(\dfrac{9}{25}\Big)^{-\dfrac{3}{2}}(12527)32×(259)−23
70×(25)−32−5−37^0 \times (25)^{-\dfrac{3}{2}} - 5^{-3}70×(25)−23−5−3
