Evaluate:
23+−45+13+25\dfrac{2}{3} + \dfrac{-4}{5} + \dfrac{1}{3} + \dfrac{2}{5}32+5−4+31+52
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LCM of 3 and 5 is 3 x 5 = 15
2×53×5+−4×35×3+1×53×5+2×35×3=1015+−1215+515+615=10+(−12)+5+615=915\dfrac{2 \times 5}{3 \times 5} + \dfrac{-4 \times 3}{5 \times 3} + \dfrac{1 \times 5}{3 \times 5} + \dfrac{2 \times 3}{5 \times 3} \\[1em] = \dfrac{10}{15} + \dfrac{-12}{15} + \dfrac{5}{15} + \dfrac{6}{15} \\[1em] = \dfrac{10 + (-12) + 5 + 6}{15} \\[1em] = \dfrac{9}{15} \\[1em]3×52×5+5×3−4×3+3×51×5+5×32×3=1510+15−12+155+156=1510+(−12)+5+6=159
∴ 23+−45+13+25=915\dfrac{2}{3} + \dfrac{-4}{5} + \dfrac{1}{3} + \dfrac{2}{5} = \dfrac{9}{15}32+5−4+31+52=159
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