Evaluate:
4−9+1\dfrac{4}{-9} + 1−94+1
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−49+11\dfrac{-4}{9} + \dfrac{1}{1}9−4+11
LCM of 9 and 1 is 3 x 3 = 9
−4×19×1+1×91×9=−49+99=−4+99=59\dfrac{-4 \times 1}{9 \times 1} + \dfrac{1 \times 9}{1 \times 9} \\[1em] =\dfrac{-4}{9} + \dfrac{9}{9} \\[1em] =\dfrac{-4 + 9}{9} \\[1em] =\dfrac{5}{9}9×1−4×1+1×91×9=9−4+99=9−4+9=95
∴ 4−9\dfrac{4}{-9}−94 + 1 = 59\dfrac{5}{9}95
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