Evaluate:
2+−352 + \dfrac{-3}{5}2+5−3
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21+−35\dfrac{2}{1} + \dfrac{-3}{5}12+5−3
LCM of 1 and 5 is 5
2×51×5+−3×15×1=105+−35=10+(−3)5=75\dfrac{2 \times 5}{1 \times 5} + \dfrac{-3 \times 1}{5 \times 1} \\[1em] =\dfrac{10}{5} + \dfrac{-3}{5} \\[1em] =\dfrac{10 + (-3)}{5} \\[1em] =\dfrac{7}{5}1×52×5+5×1−3×1=510+5−3=510+(−3)=57
∴ 2 + −35\dfrac{-3}{5}5−3 = 75\dfrac{7}{5}57
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