Evaluate:

$(8^0 + 2^{-1})\times 3^2$

$(8^0 + 2^{-1})\times 3^2\\[1em] = \Big(1 + \dfrac{1}{2^1}\Big)\times 3^2\\[1em] = \Big(\dfrac{1}{1} + \dfrac{1}{2}\Big)\times 9$

LCM of 1 and 2 is 2

$= \Big(\dfrac{1 \times 2}{1 \times 2} + \dfrac{1 \times 1}{2 \times 1}\Big)\times 9\\[1em] = \Big(\dfrac{2}{2} + \dfrac{1}{2}\Big)\times 9\\[1em] = \Big(\dfrac{2+1}{2}\Big)\times 9\\[1em] = \Big(\dfrac{3}{2}\Big)\times 9\\[1em] = \Big(\dfrac{3 \times 9}{2}\Big)\\[1em] = \dfrac{27}{2}\\[1em] = 13\dfrac{1}{2}$

$(8^0 + 2^{-1})\times 3^2 = 13\dfrac{1}{2}$